Unordered List

Monday, 21 November 2016

Differential Equations-Exercise 12.1

1.Please see the question from book.
Soln:
Or, 
Or, x.dx = y.dy
Integrating, 
So, x2 = y2 + c.
Or, x2 – y2 = c.

2.Please see the question from book.
Soln:
Or, x.dx + y.dy = 0
Integrating, 
So, x2 + y2 = c.

3.Please see the question from book.
Soln:
Or, dydx = à (y2 + 1).dy = (x2 + 1).dx
Integrating, + y + c =  + x.

4.Please see the question from book.
Soln:
Or, x2.dy – y2.dx = 0
Dividing each term by x2y2.
Or, = 0.
Integrating,  = c’
Or,  = c’
Or, - x + y = c’xy.
So, x – y = c’xy
So, x – y = cxy, where c = c’

5.Please see the question from book.
Soln:
Or, (1 + x)2= 1.
Or, dy =
Integrating, y = tan-1 x + c.

6.Please see the question from book.
Soln:
Or, 
Or, y.dy = (ex + 1).dx
Integrating,  = ex + x + c’
So, y2 = 2ex + 2x + 2c’
So, y2 = 2ex + 2x + c where, c = 2c’


7.Please see the question from book.
Soln:
Or,  + 4x = 2e2x
Or, dy + 4x.dx = 2e2x.dx
Integrating, y + 2x2 =  + C.
So, y= e2x – 2x2 + C.

8.Please see the question from book.
Soln:
Or, .dy + .dx = 0.
Dividing each term by .
Or, = 0.
Integrating, sin-1y + sin-1x = sin-1c
Or, sin-1 = sin-1c
So, x + y.= c.

9.Please see the question from book.
Soln:
Or, (1 + x)y.dx + (1 + y)x.dy = 0.
Dividing each term by xy,
Or, .dx + dy 0
Or, .dx + .dy = 0
Integrating,
Logx + x + log y + y = c.
Or, log(xy) + x + y = c.

10.Please see the question from book.
Soln:
Or, (xy2 + x).dx + (yx2 + y).dy = 0
Or, x(y2 + 1).dx + y(x2 + 1).dy = 0
Dividing each term by (x2 + 1)(y2 + 1),
Or, +1.dx + +1.dy = 0.
Integrating, log(x2 + 1) + log(y2 + 1) = .logc.
Or, log(x2 + 1)(y2 + 1) = logc.
Or, (x2 + 1)(y2 + 1) = c.

11.Please see the question from book.
Soln:
or, x. + y – 1 = 0.
Or, x.dy + y.dx – dx = 0.
Or, d(xy) – dx = 0.
Integrating, xy – x = C àx(y – 1) = C.

12.Please see the question from book.
Soln:
Or,  = ex – y  + x3.e-y.
Or, ey.dy = (ex + x3).dx 
Integrating, ey = ex +  + C.

13.Please see the question from book.
Soln:
Or, tanx.dy + tany.dx = 0
Dividing each term by tanx.tany
Or,  +  = 0.
Or, .dy + .dx = 0
Integrating,
Or, log(siny) + log(sinx) = logc.
Or, log(sinx.siny) = logc.
So, sinx.siny = c.

14.Please see the question from book.
Soln:
Or, 
Or, dydx = 
Or,  = 
Or, -cosec2x.dx = sec2y.dy
Integrating, cotx = tany + c.
So, cotx – tany = c.


If you find any mistakes in these above solutions please let me know in the comments i will greatly appreciate that. and try to correct that as well.


Share:

2 comments:

  1. Please post all the answer of old is gold ...the answer of our regular book are almost solve by tp sir ....

    ReplyDelete
  2. Okay thanks for the comment. Can you please mention in details about the portion of basic mathematics from old is gold that you want me to post.

    ReplyDelete

Support

Popular Posts

Recent Posts

Text Widget

Pages

Powered by Blogger.

Text Widget

Blogroll

Popular Topics

Follow us on G+

Be our Fan

Follow us on FaceBook

More information

Copyright © Mathematics Answer | Powered by Blogger

Design by Anders Norén | Blogger Theme by NewBloggerThemes.com